4x^2+20=10x+3y^2-4

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Solution for 4x^2+20=10x+3y^2-4 equation: 


Simplifying
4x2 + 20 = 10x + 3y2 + -4

Reorder the terms:
20 + 4x2 = 10x + 3y2 + -4

Reorder the terms:
20 + 4x2 = -4 + 10x + 3y2

Solving
20 + 4x2 = -4 + 10x + 3y2

Solving for variable 'x'.

Reorder the terms:
20 + 4 + -10x + 4x2 + -3y2 = -4 + 10x + 3y2 + 4 + -10x + -3y2

Combine like terms: 20 + 4 = 24
24 + -10x + 4x2 + -3y2 = -4 + 10x + 3y2 + 4 + -10x + -3y2

Reorder the terms:
24 + -10x + 4x2 + -3y2 = -4 + 4 + 10x + -10x + 3y2 + -3y2

Combine like terms: -4 + 4 = 0
24 + -10x + 4x2 + -3y2 = 0 + 10x + -10x + 3y2 + -3y2
24 + -10x + 4x2 + -3y2 = 10x + -10x + 3y2 + -3y2

Combine like terms: 10x + -10x = 0
24 + -10x + 4x2 + -3y2 = 0 + 3y2 + -3y2
24 + -10x + 4x2 + -3y2 = 3y2 + -3y2

Combine like terms: 3y2 + -3y2 = 0
24 + -10x + 4x2 + -3y2 = 0

The solution to this equation could not be determined.

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